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Space Math

October 22nd, 2009

The following forms use javascript to perform their calculations. Changing one variable or unit will force a recalculation. The process converts all units into MKS and the back to the desired results. This always creates rounding errors, so be aware that the results are good only to a few decimal places.

Javascript is limited to the size of the numbers it can handle and you will see that some of these calculators break down when using large accelerations for long periods of time. The universe is larger than java script can handle. Meters and seconds are pitifully small units for doing calculations involving millions of light years.

I first wrote some of these calculators about 15 years ago, and the code style reflects this. The code is fragile and every time I fix a bug I create another. If you find a bug, please let me know.

Newtonian Constant Acceleration in g's.
Use this to calculate how far a spaceship will go in a certain time at a certain acceleration. A ship going at a rate of 1g for 100 seconds will travel 49000 meters. If you put in distance traveled it will tell you the time needed to travel that distance at the specified g force. G force here is the force of gravity at the earth's surface. This does not take into account relativistic effects, so use this for interplanetary travel.
Acceleration Time Distance v=0

Acceleration in g's on a cylinder such as a space station or space colony.
Use this to find out how fast a space station must spin (period of rotation time in seconds) to maintain a certain force of gravity. You can vary the radius to get a new acceleration or vary the period to get a new radius. Changing the g force will recalculate the period. G force here is the force of gravity at the earth's surface.

Period Radius Acceleration

Period and radius of a circular orbit around a planet.
This gives you the distance from the center of planet and the time it takes for one circular orbit. The units are in terms of planet mass. I've given Earth, Jupiter and the sun for examples. (remember the earth is 6,378 km in radius so subtract that out to get distance from the surface.) Click these links to pre load set diameters Earth, Venus, Mars, Jupiter, The Moon

Period Radius Planet Mass

Escape velocity at a planet's surface
This is the speed that will allow an object to leave the gravitational field of a planet. Anything slower will be slowed down enough by gravity to fall backwards to the planet. Radius is is the radius of the planet. Click these links to pre load set diameters Earth, Venus, Mars, Jupiter, The Moon

Velocity Radius Planet Mass

Relativistic effects

Length Contraction.

The length of things shrinks in the direction of the motion. This is measurable at relativistic speeds. Enter the Rest length and a Velocity and get the contracted length. Enter the Contracted length and get the Velocity. How long will a yard stick be at 1/2 the speed of light? The answer is about 2.6 feet. This calculation is based on an Earth Observer.
Velocity Earth length Moving Length

Time Dilation.
At relativistic speeds time slows down. Enter the Rest interval and a Velocity and get the dilated time. For example how long will ten seconds appear to be when traveling at 1/2 C? Answer=11.57 seconds. This is a Little confusing. Time slows down for a fast moving space traveller which means that it looks like more seconds pass on Earth than for the traveller. This calculation is based on an observer from earth.

Velocity Moving Time Earth Time

Long Relativistic Journeys
Going to a star requires that you speed up and then slow down. It is a double calculation. Half of the trip you accelerate, but if you need to slow down for the second half so that you reach the star, not splat against it. A traveler experiences the trip at one time rate and an observer on one of the stars will experience much longer time. At 1 G acceleration, it is possible to travel to a near galaxy within a generation, but when you will come back it will be millions of years later.
Use this calculator to figure the time it takes to get to a star at constant acceleration and then constant deceleration. Counter to what we might expect, a voyager can make it to a star 20 light years away in 6 years. This is not a violation of Relativity, but a side effect.
Note: unlike the other functions I didn't include the calculation where you plug in time and get distance. That acosh got me.
Note 2: If you try for really long distances the trip time shows infinity - this is due to limitations of JavaScript.

Acceleration Distance
Trip Time Earth Time

Size of Black Holes

The Swarzchilde radius is calculated as r=2*G*M/c^2. The actual size of black holes is tiny.


Mass Radius

Conversions

Here are some conversions of units which might be used in space travel

Length Conversions

 

Energy Conversions

105 Responses to “Space Math”

  1. LarryD says:

    Keith although there various ideas around at present with regard attaining light speed (warping space for example) they remain ideas only, so we don’t have the technology to test these ideas…yet.
    Disregarding Tachyons, a photon travels a c and present theory says that a photon does not realise the passage of time and could, theoretically, travel the known universe in zero time. We, of course would record X billions of years for that photon to travel. But this suggests even deeper questions for if the photon experiences no lapse of time then…
    TOE theories have a variety of points to make but they have problems of their. Also remember that the components of photon propagation exceed c.

  2. Keith says:

    What would happen is that they would see their accelerometer or whatever calculating their current speed, but as they approach the speed of light, another frame at rest with their starting position would see their clocks start to slow down, so they would slow down more and more as their accumulator approached C. The closer they got the slower their clocks would be so that at 99.999 % of C, they would be stuck and hardly moving in time at all.

    To the travelers, the universe in front of them would appear to shrink so they would be moving past very small, but wide, stars that are packed close together. As they slowed down again the universe would go back to its normal size and very little time would have passed, but on the frame where they started, hundreds or thousands of years would have gone by. To the travelers space appeared to shrink as they stepped on the gas. To every one else, the travelers clocks would have slowed down while space remained normal.

  3. LarryD says:

    sean, I didn’t write the comment correctly. I intended that ‘IF’ the on board computer was cummulalitive. As you point out on board would probably be using a continuous form of the SR v addition equation and show the fraction of c obtained.

  4. sean says:

    @Larryd: the crew wouldn’t consider themselves to be travelling faster than c, nothing can travel faster than c when viewed from any reference frame. You’re using Newtonian logic in a relativistic setting.

  5. David says:

    This is an excellent resource. You really should consider creating a smart phone app with this. I’ve made this a favorite on my computer,

  6. jac says:

    this tool helped me to get aware that ‘a constant 1 g acceleration would permit humans to travel through the entire known Universe in one human lifetime’ and that is great idea !

  7. William Bell says:

    Good to know. :)

  8. Keith says:

    It requires a rewrite – and I’m going to do it one of these days.

    thanks,

    Keith

  9. William Bell says:

    The “Newtonian Constant Acceleration in G’s” Calculator only allows you to change the first two variables.

    Also, despite that I must say I love this and its going to be bookmarked forever because it makes things so much easier.

  10. LarryD says:

    Just found thiis website during some research. Just in case anyone is interested on board velocity can be calculated by:
    ([v/c]x[yg]x[time in seconds]/c in meters. y = number of g’s.
    e.g. ([0.999]x[100×9.8]x[86400])/c = approx 0.2822c or after 10 days approx 2.822c. So in this way the crew of the ship consider they are moving faster than light because the on board guage is cummulalitive.

  11. cygnus says:

    nice work !
    a little buggy & can be improved a bit….all calculations should be completely reversible in relation to other fields & all input fields magnitudes should be expandable @ least to the ability of the script.
    but way cool overall….Thanks !

  12. Moodie-1 says:

    The first calculator (Newtonian Constant Acceleration) is broken. It works fine if you enter time to get the distance but it doesn’t work the other way around. I tried entering 124,000 miles and got 0. Clearing and not clearing the time field before entering the distance makes no difference.

  13. eric says:

    Great page, thanks! Could you add light years as optional distance units for the first calculator of distance acceleration?

  14. Anthony Toledo says:

    What a wonderful tool for laymen writing speculative fiction! Thank you for making this superb resource available to the world.

  15. Jonathan Vos Post says:

    I argued with my later 4-time co-author Sir Arthur C. Clarke about this, and in 1969 he agreed that I was right. The relativistic multi-stage rocket equation, not within the reach of your calculators, allows for “Practical Robotic Interstellar Flight” even with fission power (which converts roughly 0.1% of mass to energy), and more easily with fusion power (roughly 1% conversion).

    See my refereed paper (republished by the British Interplanetary Society):

    INTERSTELLAR
    http://magicdragon.com/ComputerFutures/SpacePublications/STAR.html

    Hydrogen Ice Spacecraft for
    Robotic Interstellar Flight
    by
    Jonathan Vos Post, F.B.I.S.

    ABSTRACT

    Spacecraft constructed from cryogenic hydrogen (or deuterium
    and tritium) ice can use the same material for structure,
    shielding, coolant, and fuel. This type of “autophage”
    (self-consuming) spacecraft achieves an extremely low dead-weight
    fraction, which is a critical parameter for optimizing the
    performance of interstellar spacecraft.

    To reduce the volatility of hydrogen ice, a particular
    self-refrigerating structure is presented. Hydrogen ice by itself
    is imperfect as a structural element; various methods of
    stiffening by the admixture of carbon or boron fibers are
    discussed. Other cryogens relevant to specific fusion reactions
    are considered, including deuterium, tritium, boron-11, and
    saturated solutions of lithium in anhydrous ammonia.

    A quantitative analysis is presented of the relativistic
    kinematics of multi-staged interstellar iceships. In the limiting
    case of a 5-stage deuterium ice fusion spacecraft on a one-way
    mission with no deceleration at the destination, a dead-weight
    fraction of 10-1 for each stage, and a total payload fraction of
    10-5, then the final burnout velocity of the 5th stage is 0.64c,
    which at constant 0.0485 g acceleration would reach Alpha Centauri
    in 12.81 years, and at 1-g acceleration would get a probe zipping
    through the Alpha Centauri system in 6.7 years.

    Appears in: the Proceedings of “Practical Robotic Interstellar Flight: Are We Ready?”, New York University, New York City, 29 Aug-1 Sep 1994, and in Journal of the British Interplanetary Society, April 1996

  16. Andrew says:

    Amazing!
    I love the relativistic journey calculator. I am planning on going into engineering and studying the building of spacecraft and propulsion systems. Playing around with the calculator provokes some interesting thoughts- how about a time capsule- send out a time capsule and it could return to earth thousands of years later. You could also do a two-in-one mission; send a heavily shielded time capsule and a robot to take observations of a star of your choice; imagine what people would think hundreds of years later. Of course, it also raises questions about the practical application of space travel and the real difficulties in maintaining a type II civilization.

  17. JackF says:

    Thanks for this Keith. I’ve wondered about the math since I read A.C. Clarke’s “Rendevous with Rama” series in high school. Using your site for 10 or 15 minutes helped me get a much better mental model of the implications of relativity.

    A ship sets out from Earth to visit Sirius (about 8.6 LY distant) with an acceleration/decel of 1G for each half of the trip. It takes about 4.6 years ship time, and about 10.3 years earth time. A second ship heads out to visit Kepler 22B (~600 LY distant) at the same rates. The trip takes 12.5 years ship time, but over 602 earth years pass.

    I never had a firm mental picture of time dilation until I played with your calculator. STL speeds increase asymptotically, so the decimal places have incredible impact. I never visualized how much impact. Travel at .999C for 30 days ship time and 670 days pass on Earth. But travel at .999995C for 30 days and 9,486 days pass on earth. Observers on Earth see ship time slow; on-ship observers see Earth time speed up. I knew that but I couldn’t visualize it as clearly as I can now. Cool, thank you!

  18. astralith says:

    THANK YOU! THANK YOU! THANK YOU! As a sci-fi writer this is PERFECT! Never let this site go :-D

  19. Tom says:

    Let me put in a vote for relativistic energies. Especially after reading the piece of prose pollution _Last Train From Hiroshima_. It’d be nice to have a one-stop source for the energy of a nucleus traveling at relativistic speeds, to say nothing of rocks, ships, planets, and whathaveyou.

    I really appreciate the fixes you did a few months back after I bugged you and I hope that there’s enough support and you have enough time and interest to add the energy calculators to the site.

    Once again, humble and unworthy thanks from a frequent visitor.

    TK

  20. Keith says:

    That’s the truth according to Einstein. The people on the ship will see that it takes 20 years. Of course, back on earth a period of more than 32000 years will have passed. You can’t go faster than C, but the people on the ship will feel as though they did. The observers on Earth will say that their time frame slowed down. There may not be any observers left on Earth when they arrive at their destination, though.

    I wrote a story based on this called “The Short Run”. In the long run we’re all dead.

  21. jac says:

    32000 ly journey at 1G will take only 20 yrs for the ship ?
    are you sure that is correct?

  22. Yoron says:

    Hi :)

    This is a impressive effort. One thing I would love to see though is the math behind your calculations. Yeah, I’m sort of curious.

  23. Maggie A says:

    Just a courtesy notice that I linked your site in my piece “Star Wars, Einstein and When Lucas Got It Right” ( http://members.cox.net/maggieameanderings/2011-Oct-16.htm ). And thanks……this page perfectly illustrated, in an easily understood way, the point I was making.

  24. Fernando Torres says:

    Hi Keith, this is a nice calculator. I have a suggestion for Long Relativistic Journeys, can you add the Average and Peak speeds in terms of c (and maybe other units)? Thanks.

  25. Tom says:

    Hey, Keith. Just wanted to thank you again for the calculators and for the fix, some months back, on the units gadgets.

    If you ever have the time/inclination to do the velocity/mass->KE calculator you’ll be an even bigger hero in my book. After much frustration I’ve got my TI calculator to give mostly believable numbers but I’d be happier if I could compare them to your proven QA.

    Many thanks!

    -Tom

  26. Rick Novy says:

    I stumbled across this resource today and have already shared it with the writers who follow me on Twitter.

    Shoot me an email if you want some help with those acsh calculations for the relativistic travel tool.

  27. C. Albert says:

    Thanks, Keith! I’m fairly conversant with several sciences on verbal, graphical and statistical (as they are concrete) levels, but not the math. I only passed basic calculus via memorization & a generous curve (managed a B, but I remember nothing but the graphical concepts and that there was a lot of trig having nothing to do with measuring the height of flagpoles). I couldn’t do the relativistic calculations on my own, and was excited to find this site to generate plausible numbers for my sci-fi stories. Your other sections are thought-provoking as well. At the risk of offending your Weasel Word Detector: thank you very much for your time & generosity in providing this tool.

  28. Ivan says:

    I love this page, thank you. It would be cool to have fuel/payload ratio for long distances assuming some theoretically perfect engine.

  29. Keith says:

    It works for me

    1 second at .5C is 1.1547 observed time. going the opposite way. If you observe a ship going .5C for one second, the ships passengers will age .866 seconds.

    Keith

  30. Glenn says:

    Hey, I’m not getting any results out of the time dilation section. I’m curious to know the dilation that a speed of 0.5c will spit out.
    Can you help?

    Cheers
    :)

  31. Rob says:

    This is a great tool. I usually just do these calculations in my head or on a regular calculator if I’m lazy. It’s nice to have a quick cheat to see if I have a mistake. Keep up the good work.

  32. Keith says:

    But the way relativity works, the ship would be standing still with no kinetic energy. The universe would be moving at it with huge kinetic energy. The frame of motion of the observer is always at rest.

  33. Rod Rogers says:

    Catastrophic for the non-C object, perhaps. Not so much for the ship traveling at .9999999 C, with its huge kinetic load all the way down to the sub-atomic level. Seems to me it would be doing the vaporizing instead of being the vaporizee.

    Imagine trying to take a fix with sensors. Nothing but blue-shifted garbage coming in from up front, where 18 hours of data might arrive in a few seconds, and from astern, data red-shifted to…well nothing. Can’t detect the incoming photon because it takes too long to be detectable. Might be a 360 deg ring around midship, but somehow that concept seems to elude my imagination.

  34. Keith says:

    Some people say that collisions with objects, because of the relativistic energies involved would be catastrophic. A spec of dust moving towards us at .99999% of light would weigh tons and would not be stoppable by any kind of shield. Remember, even at this high speed, it appears to us that we are standing still and the rest of the universe is coming up to hit us in the face at .99999% C.

    I am going to see if I can make a Relativistic Kinetic Energy calculator

  35. Rod Rogers says:

    It takes a lot of 9’s behind the decimal point to really dilate time for the travelers. Essentially as their time dilates, the rate of acceleration drops toward zero, never getting there of course, just like they never get to the speed of light.

    But while pouring on the power, time continues to dilate, making a very long trip, like 500 light years, pass in just days for the travelers, while 500 years go by in real-time.

    In my current plot, one of the characters constructed a virtual chronometer which compares ship’s time and real time, giving a sense of the passing years in real-time as the 9’s mount up behind the decimal point. At the point of flip-over, three months pass in about 150 seconds. This takes at least nine more nines behind 99% and a prodigious impulse engine – like a beam core antimatter source where the fuel has two orders of magnitude more energy than fusion.

    It is an awesome set of tools however. Much better to be composing the prose instead of doing the math long hand.

  36. Keith says:

    You would have to split it up into two calculations. First calculate just the acceleration of the trip based on how fast you want to go using the trip calculator. Then use the time dilation calculator to .999% for a length of time and add the results of both to get the total trip.

    Keith

  37. Cameron says:

    This is really an awesome webpage. I stumbled across it when I was randomly Googling interstellar propulsion. I have one question about constant acceleration drives. Once a ship is nearly at the speed of light, is it necessary to keep accelerating to get the same kinds of speeds indicated in the “Long Relativistic Journeys” section?

    Basically once one gets to 0.999% C, can they just coast for the light speed portion of the trip to save fuel for the deceleration, or do they need to keep adding .9’s to the percentage (if that makes sense). Oh, and I realize that the answer is probably “no” to the first and “yes” to the second, but I’m curious how much difference those extra .9’s make in journey time (for both traveler and Earther).

  38. Anthony says:

    I use to do these calculations when I was a kid on my TI-83. Very cool to see someone else writing these programs for people.

  39. Rod Rogers says:

    Looks like you got it. In a day or two, I’ll be back into the long haul acceleration thing and it will get a workout then.

    Intuitively, I get how Newtonian acceleration blends with time dilation. If you pile on 1000g acceleration for ten hours, you end up going faster than light with the Newtonian tool. But the ship doing 1000g’s would never get to ten hours as time dilation would slow the relative (ship) passage of time as the velocity approaches .999999+ percent of C.

    Using the Relativistic Journey tool, I can approximate what that dilation is and how it affects the plot. Super tools. Thanks for sharing them.

  40. Keith says:

    Another round of fixes. I am interested in seeing what new bugs I have introduced.

    Keith

  41. Rod Rogers says:

    I’m 64. When Digital was acquired by Compaq, I got a golden parachute into the promised land (Montana). Never regretted it.

  42. Rod Rogers says:

    Nope…that didn’t work. 1g for 1hr = 32ft/hour

    You might need some quiet time to fix this.

    There’s an additional problem now where changing the time duration interval now changes whatever you had in the time box in terms of units.

    And if I change the force level, that also changes the time duration interval now, which can be an irritation when trying to work backward from a desired plot result.

  43. Keith says:

    I am 60 and I am looking forward eagerly to retirement. Wife seems to think I should work forever, though.

    Keith

  44. Rod Rogers says:

    Understood. Time eventually changes that problem — trading age for greater freedom. I think it’s terrific that you’re maintaining this resource. I’d hate to be doing the math required otherwise.

  45. Keith says:

    I made another change. I think this might be it. Please check Newtonian acceleration to see if I have it right.

  46. Keith says:

    Working on it. This darn job requires me to do uninteresting stuff for long periods of time (sometimes 8 hours at a time). I know what is wrong, I just need a few minutes to fix it.

    If the boss goes to a meeting I can get it done.

    Keith

  47. Rod Rogers says:

    It seems like the duration link to velocity is broken; I.E. velocity doesn’t update if I change from seconds to minutes or hours. Incrementing the force level changes the velocity, but not the duration.

  48. Keith says:

    Rod,

    I do updates at home and sometimes at work. I made changes to the code, but I did not download the latest version from the website first. As a result, I re-introduced the old bug.

    I use Subversion for my programming projects and it looks like it is time to start at website subversion repository so I can keep track of changes like this. Now I have to go and debug the same thing all over again and I can’t remember what it was that I fixed.

    Keith

  49. Rod Rogers says:

    Oops, looks like a new bug.

    velocity box on Newtonian acceleration. Changing from seconds to minutes or hours or days yields bad data.

    Seemed to work well enough about a week ago.

  50. Keith says:

    The Long Relativistic trip calculator does exactly this. I think this is what you are asking for. Where it says earth time, it places the time for an observer who does not make the trip, and remains behind (not necessarily the earth, of course.)

    Keith

  51. John says:

    this is great. There’s one thing I think you could use here… a way to calculate the earth-observed time versus traveler’s observe time between two points at a given rate of acceleration.

    example: spaceman spiff leaves earth at an acceleration rate of 1 G. How long will it take him to travel from earth to, say sirius (10 ly) assuming he accelerates at that rate the entire time and decelerates at the same rate when he reaches the halfway point? What amount of elapsed time does an observer on earth see and what would the ship-board time be?

  52. D says:

    Sorry about the typo misspelling of your name Keith.

  53. D says:

    Late coming back to comment Kieth, but it is good to see you’re maintaining such a useful site and right on top of squashing little bugs. Kudos! And thanks.

  54. Keith says:

    Got it. It looks like it works now. I just hope that I didn’t introduce a new bug.

    Keith

  55. Keith says:

    I fixed the units thing. It not converts to the various unit correctly so if you change from meters to feet it does the conversion. Same with hours.

    Nope, I just tested it and it is not doing the conversion on all events. Change the values – it works. Change the units and it doesn’t. Back to work.

  56. Keith says:

    I am not seeing it. It uses the time from the time duration and the distance unit from the distance. The answer should be the acceleration times time and it should correct for units. I will try some different calculations and see if it breaks.

    Keith

    Ok, I see where it is not converting back to the correct unit. It works correctly for meters and seconds, but it is not converting back to feet correctly.

  57. D says:

    Ah, I see where your calculator seems to be screwing up. I input my units and selected hours from the drop down for time. This changed the units in the v output, but did not change the actual value.

  58. D says:

    The first calculator “Newtonian Constant Acceleration in g’s.” seems to be displaying the wrong units for v in the velocity result listed as meters/hour when I use it. It should be meters/second.

  59. Mark Toner says:

    The 1G in spaceship frame is the best idea as it helps get around all those medical problems they have on the ISS. That’s why I’m adopting this calculator for an up and coming episode of my web comic. I may get to that bit before the end of the year. :)

  60. Steve says:

    Beautiful! Just had to ask… Thanks for such an amazing resource!

  61. Keith says:

    The acceleration is from the reference frame of the ship. 1G is convenient because the people in the ship would feel a “normal” gravity and get all of the health benefits of this on a long trip.

    Keith

  62. Steve says:

    Hi, I have a question about the “1G” used in the constant acceleration calculater:

    Which reference frame are you using to hang the “1G” in? I think maintaining 1G in the earth reference frame would be impossible but not necessarilly in the traveler’s reference frame (if they have a magic fuel source). Within their reference frame 1G always requires the same energy/time input no matter what so it stays manageable from their perspective. The same energy input (for them) yields the same acceleration “G” experience for them regardless.

    From the earth reference though I think energy input is dropping the longer they accelerate (as they approach C) because their time is slowing down. Eventually their clock is running so slow that what they call “1G” is negligable in our reference frame. Maybe the Lorentz transform cancels it all out with the mass increase, I’m not too sure of that.

    But I do think you have to use the traveler’s frame to calculate the 1G, otherwise they get smooshed as their time slows relative to earth frame and they experience relative acceleration much higher than it looks to us. If you’re not using the traveler’s reference to calculate the 1G then the travel time calculation is probably giving a shorter answer than it should.

    I’m guessing you did the right thing because this all looks pretty thorough but wanted to ask the question.

    To everyone who thinks relativity isn’t real – it’s already been said – throw away your GPS because if relativity isn’t real, GPS won’t work. All the calculations for GPS require precision time for every satellite in the constellation, and all of these GPS satellites experience enough relativistic time dilation (all traveling in different directions) to screw up your GPS, unless they adjust the calculations to accomodate relativity. Every time you use a GPS, you prove Einstein was right.

  63. John B says:

    I probably shouldn’t be so condescending but I won’t believe it until the day (decade?) I actually climb on a 1G perpetually accelerating self contained spacecraft and perform that 4+ year experiment myself. I’ll arrive back here at Earth and the clocks and calendars in my spacecraft will be the same as the clocks and calendars on Earth. Time travel is science fiction. Anyways – I’ll never be around to see that day. Thanks for the way to calculate the speed at the end.

  64. Keith says:

    If you want to find how fast your are traveling at the end, just multiply acceleration times the time traveled. I should have made final velocity the fourth box, but it is easy enough to figure in your head.

    No one is asking you to agree. The evidence is overwhelming, though, with thousands of experiments proving general relativity. You might say that the atomic bomb is impossible, but many people know otherwise, and the atomic bomb would be impossible if the calculators here gave different results.

    Observations of the planet Mercury, whose mass and size are altered by the relativistic effects of the Sun’s gravity, proves Einstein’s relativity with a great deal of accuracy.

    Don’t express your opinions around anyone who knows a little about physics, or you may get teased.

    Keith

  65. Bryan with a Why says:

    John – your GPS device has to correct for the theories that you claim that there is no evidence. There is empirical evidence for time dilation. http://en.wikipedia.org/wiki/Time_dilation#Experimental_confirmation

  66. John B says:

    I don’t agree with all these scientific hypothesis that a ship accelerating at 1G shrinks or grows in size/ becomes heavier or lighter. passes one year of time while 2 years pass back on earth etc etc.. Where do any of these people get one shred of evidence for all of these mathematical theory claims? Non scientifically a ship at 1G constant acceleration reaches the speed of light in 300-400 days? then it turns around – slows down for 300-400 days. Then it repeats the process in the opposite direction and ends up back here on Earth at the same day / same time on it’s on board clocks and Calendars. None of you have any proof that time or mass changes. When they develop the ability to travel that way they’ll look back at all your far out inaccurate undecipherable scientific double talk theories you had to that effect in this time and laugh at you.

    Also the one parameter I think would be helpful on the first calculator (Which is great by the way,excellent job)Is.. What speed would you be going after say a 10 day 1G acceleration. Not how many billions of milimeters did you travel.

  67. Keith says:

    I am not sure what you mean. The constant acceleration is probably necessary because of people living on the ship would not be able to live long on high acceleration (gravity like force). The calculations take the increase in mass into account.

    The motive force, however is not specified and would involve technology that we do not have at this time. The huge amount of energy needed to produce the constant acceleration is beyond humans.

    Reaching C is not an issue. You can only approach C. Increasing the acceleration only gets you closer. There is no way to obtain C as a speed. It is a limit not a target. It is not a technological issue. The C limit is a property of the universe, not something that is hard to do. The universe makes it impossible.

    In Science Fiction, C is usually sidestepped by leaving normal space/time and traveling outside of the normal universe (eg. Warp Drive in trek). Unfortunately, Warp Drive, is meaningless term and although there are some ideas, there is no proven way to accomplish it. None of the theories even look likely to be practical.

    Keith

  68. branx says:

    Hello and thanks for the wonderful calculator!

    Would it be possible to have a long relativistic journey calculator based on propulsion force instead of constant acceleration?

    If i’m not mistaken the mass gets bigger when velocity goes towards c.
    I think if the spacecraft could reach c, the mass would be infinite?

    I have no idea how hard that would be to do script or if I am even correct.

    thanks anyway,
    Branx

  69. Keith says:

    Thanks,

    Every time I upgrade the site, something new breaks.

    I’ll work on that – in the morning.

    Keith

  70. Tom says:

    Can’t thank you enough for putting these up. Only issue is that the “conversions” calculators seem to be broken. Everything else works perfectly with FF v4.0.1 but the last two don’t seem to want to update anything.

    Or, *Much More Likely*, am I doing something blatantly stupidly wrong?

    ¡Muchas Gracias!

  71. Keith says:

    You plug in the speed.

    It can be from 1mph to 99.99999% of C. You enter what you like and see how long it takes.

    Keith

  72. Chuck says:

    Does the long distance relativistic calculation assume that your top speed is just short of the speed of light?

  73. Keith says:

    You are right. The second ship will arrive 6 months after the first. The time it takes to get to Woozle will be the same for both ships.

    Keith

  74. ValZ says:

    I have a relativity qustion… Suppose planets Earth and Woozle are basically stationary with respect to one another. Suppose you have two spaceships, A and B. Suppose A leaves Earth for Woogle (to set up a base), and then six months later in earth’s frame of reference, B leaves Earth for Woogle (resupply mission). Both ships have the same acceleration schedule (say, 1g acceleration first half of trip, 1g deceleration second half of trip). Will B arrive at Woogle six months after A does, by the Woogle base’s chronometers? If not, why not?

  75. roobub says:

    i need for a school project a program for a relativistic travel calculator, i have no idea how to do it. if someone knows how to do one could you please post or mail it.?
    thanks X X

  76. Mark says:

    Thanks, Keith.

    This is much more accurate than my rough approximations. I’ll be making use of this in a month or two in my Gail Scott comic. I’ll be sure to put in some references on the site.

  77. Keith says:

    see: http://en.wikipedia.org/wiki/Proper_acceleration

    For constant unidirectional proper-acceleration, similar relationships exist between rapidity η and elapsed proper time Δτ, as well as between Lorentz factor γ and distance traveled Δx. To be specific:

    \alpha=\frac{\Delta w}{\Delta t}=c \frac{\Delta \eta}{\Delta \tau}=c^2 \frac{\Delta \gamma}{\Delta x},

    where the various velocity parameters are related by

    \eta = \sinh^{-1}\left(\frac{w}{c}\right) = \tanh^{-1}\left(\frac{v}{c}\right) = \pm \cosh^{-1}\left(\gamma\right) .

    These equations describe some consequences of accelerated travel at high speed. For example, imagine a spaceship that can accelerate its passengers at “1 gee” (or 1.0 lightyears per year squared) halfway to their destination, and then decelerate them at “1 gee” for the remaining half so as to provide earth-like artificial gravity from point A to point B over the shortest possible time.[8][9] For a map-distance of ΔxAB, the first equation above predicts a mid-point Lorentz factor (up from its unit rest value) of γmid=1+αxAB/2)/c2. Hence the round-trip time on traveler clocks will be Δτ = 4(c/α) cosh−1(γmid), during which the time elapsed on map clocks will be Δt = 4(c) sinh[cosh−1(γmid)].

    This imagined spaceship could offer round trips to Proxima Centauri lasting about 7.1 traveler years (~12 years on Earth clocks), round trips to the Milky Way‘s central black hole of about 40 years (~54,000 years elapsed on earth clocks), and round trips to Andromeda Galaxy lasting around 57 years (over 5 million years on Earth clocks).

  78. Mark says:

    Are your relativistic calculations made using four-dimensional acceleration w=c^2du/ds or are they made by small increments of velocity under Lorenz transforms?

  79. Brian says:

    Thanks! :)

  80. Keith says:

    It is done.

    Keith

  81. Brian says:

    Keith/admin, please, please put in a carriage return/line feed at the end of the “relativistic journeys” one!!! The “earth time” is not visible; it does not appear to be visible in either Firefox or IE. Although I think it would just be the same as the distance in light years, right?

    –Brian

  82. Keith says:

    I haven’t coded in C for 20 years. JavaScript is easy enough to translate to C, though. You should give it a try.

    Keith

  83. roobub says:

    could you make a program for it in c please? x x

  84. haysoos says:

    Just found this site. Excellent stuff!

    I didn’t see an answer to Will’s question – whether or not the first calculator was for the trip under constant acceleration the whole way, or for the trip with deceleration at half way, so the ship arrives at 0 velocity. I’m assuming it’s constant acceleration (since that’s what it actually says).

    Also, it would be great if Astronomical Units (AUs) was an option under the units of distance.

  85. Brian says:

    In the “long relativistic journeys” part, you need to add a line feed; the far right part of the calculator is not visible.

  86. Carl says:

    These calculators are awesome!

    I’d like to point out human jet fighter pilots routinely experience G forces in the 9G range. A G suit is required, and they can only handle it for a few minutes without blacking out. Humans have survived G forces over 50, for a very short time–but with permanent damage to the brain and eyes.

  87. Benjamin says:

    G force is not additive at constant acceleration. G force is constant at constant acceleration. If a ship is traveling at one G, then the occupants feel earth like gravity the whole way. If the ship is traveling at two G, then the occupants feel twice as heavy the whole way. If you have them travel at 0 g then they will be weightless and the ship will coast in the direction you sent it, but not accelerate at all.

    What you really want to do is go half the distance between Earth and Mars accelerating at N G, then turn the ship around and accelerate at N G, where N is the acceleration you are traveling. (I don’t recommend above 2 G with humans on board. It makes walking around the ship difficult.) You should end up at rest in the orbit of Mars. 1 g will take 1.8 days.

  88. Mike Hriczo says:

    OK , at 1 G constant acceleration it says 1.2 days to reach Mars at its closest point to Earth. Not counting deceleration to reach surface. My question still is if G force is additive at constant acceleration humans would perish at 30 Gs right? Therefore a reasonable cruising speed is need at which point constant velocity would yiled 0 G force until time to deceleration or make turns. Some one guide me on this please. the new show on Discovery Channel ” Bad Universe” seems to have got this wrong.

  89. Keith says:

    NaN is Not a Number. Either your used commas in your numbers or there was a divide by zero or a number was too big.

  90. Mike Hriczo says:

    For space travel conversion I PUT IN 36,000,000 Miles ( MIN. TO MARS) at i G.
    It gave a time of NaN. What is NaN? Also Is the G force additive to the human
    body at a constant acceleration? Could human body survive or would a constant
    velocity at a high speed with no G force be best way to travel ?

  91. Will says:

    Great site thank you very much. My question is in regards to your first calculator; does it calculate the trip time based on accelerating at Xgs half way, turning around, and decelerating? Or is it just a straight shot past whatever destination? I am not great at math but is it safe to assume I can cut the distance in half, double the time and arrive at my destination at 0c relative to that position?

  92. Chuck says:

    Thanks for the answer. The reason I was wondering was that I found that using the Newtonian Constant Acceleration in G’s put me at 99.99% of c at 354 days of 1g acceleration. The story I am writing involves communication between a person on Earth and another in a ship traveling to another solar system. I’m using speed of light communication and having to determine distance at various points of the journey and calculating time needed to receive transmissions.

    Thanks again – this is a great site!

  93. Keith says:

    You can’t max out. At the end you accelerate all that you want and only make it a little closer to C. C is the boundary and you can very close, but no patter how you push you can only get little closer. In a long trip you might get to 99.999… with 1000 nines, but you can’t hit C.

    A person or animal or any object that is under length contraction can’t tell and will think everything is normal. Even yardsticks will shrink so as far as they are concerned, they are not contracted.

    Keith

  94. Chuck says:

    In your formula for Long Relativistic Journeys, what percentage of speed of light (c) did you max out at? Also, theoretically, how would Length Contraction affect a living organism?

  95. Jon B says:

    Awesome! If you travel at the highest known non-light speed acceleration (which would land you anywhere infinitely instantaneously from the travelers perspective at least), you would accelerate at 10^12 g’s, the acceleration experienced in free fall into a neutron star. If you accelerated at a constant rate for ~2 minutes 49, then decelerated with the same force for the same amount of time, you would reach the end of the known universe, 13 billion light years from home. Of course, by then, the Earth and our solar system would have long since passed into dust (just a few seconds after launch, from the travelers perspective), but you would have lived to see the physical boundary of space!

  96. Jon B says:

    Thanks for posting! I wish some idiots would answer the Yahoo questions correctly regarding relativistic travel. The major misconceptions about it should be corrected! Glad to see somebody is publishing correct information though.

  97. GrimAura says:

    Just wanted to say thanks. Took me 4 hrs to find these. Although being a math idiot I think I learned some stuff trying to find it.

    G®îMÅü®Å <<<<<<Hates formulas :)

  98. Benjamin says:

    Keith, I meant how old is the other twin in the twin paradox? How much time passes for the observer on Earth when his brother on the ship returns.

  99. Keith says:

    You double it for round trip. The trip to Tau Ceti takes 12 years. That’s the time that passes for the crew. An observer form Earth will think that it took longer, but the crew doesn’t “seem” to take 12 years, they actually do take 12 years. It takes 12 years, or it takes more than 20 years depending on where you are standing. Time is not constant.

    A calculator to figure how long it takes to get to a planet and back based on a constant acceleration on the ship can be done, but I’d have to think about it. It is probably as simple as turning the relativistic trip calculator inside out.

  100. Benjamin says:

    I like the calculator for long planetary voyages. The relativity threw me off though. How much time passes if the ship makes a round trip? If a ship goes from Earth to Tau Ceti (about 20 ly) and back, it should take more than 12 years even if it just seems like 12 years to the crew on the ship.

  101. N Kalanaga says:

    The gravity calculation is easy, as long as you settle for Earth-units. The formula is Mass/(Radius^2)=Gravity, with Mass in Earth masses, Radius in Earth radii, and Gravity in Earth gees. If you need meters/sec multiply the result by 9.8, or as accurate as you want to take it.

  102. Graham says:

    These look good. But what I’m looking for is a calculator that you can input the planets gravity & radius and determine the planets mass.

  103. These are fabulous! Thanks!

  104. admin says:

    Most of them you can. Change one and another one will change. I’ve tried to make it work that way. I have a half done page of a more of these with some of the formulas fixed to make them easier to use.

    Keith

  105. adrian says:

    would have been nice to go the other way with some of these like i know the 2 lengths of time but don’t know the velocity

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